Two of MLB's smallest spenders will meet in the World Series for first time since 1991
NEW YORK (AP) -- When the Milwaukee Brewers defeated the mighty, monied Los Angeles Dodgers on Thursday night, it set up the first World Series betwee
When the Milwaukee Brewers triumphed over the Los Angeles Dodgers on Thursday, it marked the first time since 1991 that two of baseball's smallest spenders would face off in the World Series. The series will begin on October 23, with Milwaukee taking on either Cleveland or Tampa Bay. This encounter will be the first such matchup between two of the lowest-paid teams in the league since 1991.
The Dodgers, New York Mets, and New York Yankees will watch the games from home, as their payrolls far exceed those of the Brewers, Guardians, and Rays. The impending World Series comes just six weeks before a potential management lockout, which could jeopardize the 2027 season. MLB Commissioner Rob Manfred advocates for a salary cap, arguing that it would level the playing field and ensure a more competitive environment.
However, players argue that teams with larger payrolls already have the resources to compete effectively. The last time two pennant winners were among the bottom half of spending teams was when Minnesota beat Atlanta in 1991. No small-market team has won the World Series since Kansas City in 2015.
Written by urgent.news from The Mainichi's reporting — not their text. Machine-written — may contain errors; check the original before relying on it.
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