De Minaur gets qualifier in first round as US Open draw announced
Alex de Minaur appears to have a kind draw for the year's final grand slam, but Australia's perennial hope will face a precociously formidable obstacle if he wants to make it to the quarterfinals for the third straight year.
In the recently announced US Open draw, Australian tennis player Alex de Minaur will face a qualifier in the first round of the tournament. De Minaur is currently the world number six and has won the French Open this year, making him a strong contender for the US Open title. However, he will have to overcome a precocious opponent if he hopes to advance to the quarterfinals for the third consecutive year.
There are a total of 13 Australian players competing in both the men's and women's singles, with three more in the final rounds of qualifying. The US Open, the final Grand Slam of the year, will commence at Flushing Meadows in New York next week. De Minaur's draw appears kind for the year's final grand slam, but he will face a formidable obstacle in his path to the quarterfinals.
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